The Arithmetic Mean - Geometric Mean Inequality

There are many problems in engineering and science where we work with the arithmetic mean

xAM=x1+x2++xnnx_{AM} = \frac{x_1 + x_2 + \dots + x_n}{n}

or the geometric mean

xGM=x1x2xnnx_{GM} = \sqrt[n]{x_1 \cdot x_2 \cdot \dots \cdot x_n}

While these are two different ways of combining a number of sample points, we can prove the Arithmetic Mean - Geometric Mean (AM-GM) Inequality, which is a useful result that tells us that the arithmetic mean cannot be smaller than the geometric mean, and that these two measures are equal if, and only iff, the numbers are all equal.

Formally, the AM-GM inequality is stated as

For any set of nonnegative real numbers {x1,x2,,xn}\{x_1, x_2, \dots, x_n\} the arithmetic mean xAMx_{AM} and geometric mean xGMx_{GM} are related by xAMxGMx_{AM} \geq x_{GM} The equality xAM=xGM=μ x_{AM} = x_{GM} = \mu holds iff i{1,2,,n}:xi=μ\forall i \in \{1, 2,\dots,n\}: x_i = \mu

If we consider the case that n=2n = 2, the AM-GM inequality becomes

For any x1,x2x_1, x_2 \geq 12(x1+x2)x1x2\frac12\left(x_1 + x_2\right) \geq \sqrt{x_1 x_2} The equality holds if and only if x1=x2x_1 = x_2.

The AM-GM inequality is a useful tool in a number of optimisation problems.

For example, consider an optimsation problem where we are trying to find the values of x1x_1 and x2x_2 so that their product x1x2x_1 x_2 is maximised.

Suppose we are told the sum of these values can be no greater than some value SS. This tells us that

x1+x2S12(x1+x2)S2xAMS2\begin{aligned} x_1 + x_2 &\leq S \\ \frac12\left(x_1 + x_2\right) &\leq \frac{S}2 \\ x_{AM} &\leq \frac{S}2 \end{aligned}

By using the AM-GM inequality xAMxGMx_{AM} \geq x_{GM}, we can now establish that

xGMS2x1x2S2x1x2S24\begin{aligned} x_{GM} &\leq \frac{S}2 \\ \sqrt{x_1 x_2} &\leq \frac{S}2 \\ x_1 x_2 &\leq \frac{S^2}4 \\ \end{aligned}

The AM-GM inequality doesn't just set the upper bound, it also tells us the conditions under which this maximum will be achieved, which is when x1=x2 x_1 = x_2. Since we know that x1+x2=Sx_1 + x_2 = S, we can conclude that x1+x2=S2x_1 + x_2 = \frac{S}2 . will give us the largest value of x1x2x_1 x_2.

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