Question 11(c)

Using the substitution u=x1u = x - 1, find xx1dx\displaystyle \int x \sqrt{x - 1} dx

Solution

This is an example of performing integration by substitution. To solve this, we can apply The Change of Variables Theorem

g(u(x))u(x)dx=g(y)dywhere y=u(x)\int g(u(x)) \cdot u'(x) dx = \int g(y) dy \quad \text{where } y = u(x)

where

u(x)=x1g(u(x))u(x)=xx1\begin{aligned} u(x) &= x - 1 \\ g(u(x))u'(x) &= x \sqrt{x - 1} \\ \end{aligned}

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